Chicago massive voter fraud proven!
Posted: Tue Sep 05, 2017 3:49 pm
National average was about 50% of eligible voters actually cast ballots (half for each R and D). Of all registered voters, roughly 25% for Trump and 25% for Hillary.
However, the diligent voters in Chicago (always won by Demo-rats), this election season were so keen on exercising their Constitutional vote that not only did everyone vote, but MORE people voted than are registered to vote!
http://chicagocitywire.com/stories/5111 ... in-chicago
W.J. Kennedy | Aug 25, 2017
Illinois National Election:
Clinton: 2,977,000
Trump: 2,118,000
Other: 300,000
Now who do you suppose all those illegal votes go to in Chicago? Here are some hints:
* Dems always win Chicago elections
* Chicago carries the state of Illinois in National elections
* Dems are the party against voter ID laws, cleaning up the voter rolls, etc.
Trump lost Illinois by about 860,000 votes. Maybe enough fraud in Chicago to make that up, or maybe not. However it's fair to extrapolate that with a national average of 50% voting participation, and 25% of the remainder going Trump and 25% going Clinton, then Illinois would have been RAZOR THIN.
Put it this way. These are rough figures, not exact, for the sake of discussion.
We can assume that 1/2, or 550,000 votes were fraudulent and 100% democrat, so deduct that from Hillary's totals.
Clinton: 2,977,000 - 550,000 = 2,427,000
Trump: 2,118,000
Now, that still doesn't get Trump the votes he would have needed. But given that all the other great lake states and midwest states (except Minnesota) went Trump, it's fair to say that he should have gotten votes even in Chicago akin to the nations split of about 50% of voters.
Deduct another 50% or around 275,000 votes and give those to Trump, increasing his totals by same.
Clinton: 2,977,000 - 550,000 - 275,000 = 2,152,000
Trump: 2,118,000 + 275,000 = 2,393,000
Now, maybe these are pie-in-the-sky figures. But Trump won all the midwest states and great lake states except Illinois. He won Ohio, Indiana, Michigan, Wisconsin, Missouri, Iowa, Kentucky, and Pennsylvania. Kinda makes you wonder about Chicago and presumably about a half million illegal votes.
This is speculation, and my figures may be off 100k here and there. But the point remains that Chicago is an outlier. In a city with abysmal education and poverty and apathy levels, it's not only improbable, but unlikely and example of fraud when 100% of voters cast ballots, and clearly fraud when significantly MORE than 100% cast ballots. And that fraud clearly would have aided Hillary.
Hmmmmm.....
However, the diligent voters in Chicago (always won by Demo-rats), this election season were so keen on exercising their Constitutional vote that not only did everyone vote, but MORE people voted than are registered to vote!
http://chicagocitywire.com/stories/5111 ... in-chicago
W.J. Kennedy | Aug 25, 2017
More than 14,000 votes were cast in Chicago during the 2016 general election than there were voters to cast them, based on separate figures released by the Chicago Board of Elections, the chairman of the Chicago Republican Party has reported.
Chris Cleveland told the Chicago Wire that "on a whim," he filed a Freedom of Information Act (FOIA) request with the board, which provided him with a list of 1,101,178 people who voted in the general election. An earlier post on the board's website said that 1,115,664 votes had been cast.
Illinois National Election:
Clinton: 2,977,000
Trump: 2,118,000
Other: 300,000
Now who do you suppose all those illegal votes go to in Chicago? Here are some hints:
* Dems always win Chicago elections
* Chicago carries the state of Illinois in National elections
* Dems are the party against voter ID laws, cleaning up the voter rolls, etc.
Trump lost Illinois by about 860,000 votes. Maybe enough fraud in Chicago to make that up, or maybe not. However it's fair to extrapolate that with a national average of 50% voting participation, and 25% of the remainder going Trump and 25% going Clinton, then Illinois would have been RAZOR THIN.
Put it this way. These are rough figures, not exact, for the sake of discussion.
We can assume that 1/2, or 550,000 votes were fraudulent and 100% democrat, so deduct that from Hillary's totals.
Clinton: 2,977,000 - 550,000 = 2,427,000
Trump: 2,118,000
Now, that still doesn't get Trump the votes he would have needed. But given that all the other great lake states and midwest states (except Minnesota) went Trump, it's fair to say that he should have gotten votes even in Chicago akin to the nations split of about 50% of voters.
Deduct another 50% or around 275,000 votes and give those to Trump, increasing his totals by same.
Clinton: 2,977,000 - 550,000 - 275,000 = 2,152,000
Trump: 2,118,000 + 275,000 = 2,393,000
Now, maybe these are pie-in-the-sky figures. But Trump won all the midwest states and great lake states except Illinois. He won Ohio, Indiana, Michigan, Wisconsin, Missouri, Iowa, Kentucky, and Pennsylvania. Kinda makes you wonder about Chicago and presumably about a half million illegal votes.
This is speculation, and my figures may be off 100k here and there. But the point remains that Chicago is an outlier. In a city with abysmal education and poverty and apathy levels, it's not only improbable, but unlikely and example of fraud when 100% of voters cast ballots, and clearly fraud when significantly MORE than 100% cast ballots. And that fraud clearly would have aided Hillary.
Hmmmmm.....